Track Night in America comes to Daytona!
Posted: Tue Jul 09, 2019 7:51 pm
Daytona International Speedway on August 1st, 2019 will host an event called Track Night in America.
If you've ever wanted to drive the Daytona Rolex course, now's your chance!
The full details can be found here: https://www.tracknightinamerica.com/eve ... a-august-1
In a nutshell, you can do this event even if you have zero track experience, and participate at a level that is comfortable to you. There are opportunities for track "parade laps" all the way up to "as fast as your pucker allows."
All you need is long pants, a shirt, closed toed shoes and a helmet. And a street car that is licensed and insured. If it's a convertible, there are added requirements you can read about on the page below. If it's a non street legal race car, you might not be allowed into this event. There is a Track Event the following day that you can sign up for. See my other SCCA post in this forum.
So study the link, and also the What to Expect page here: https://www.tracknightinamerica.com/pag ... -to-expect
And register to come out and play!
Tom
If you've ever wanted to drive the Daytona Rolex course, now's your chance!
The full details can be found here: https://www.tracknightinamerica.com/eve ... a-august-1
In a nutshell, you can do this event even if you have zero track experience, and participate at a level that is comfortable to you. There are opportunities for track "parade laps" all the way up to "as fast as your pucker allows."
All you need is long pants, a shirt, closed toed shoes and a helmet. And a street car that is licensed and insured. If it's a convertible, there are added requirements you can read about on the page below. If it's a non street legal race car, you might not be allowed into this event. There is a Track Event the following day that you can sign up for. See my other SCCA post in this forum.
So study the link, and also the What to Expect page here: https://www.tracknightinamerica.com/pag ... -to-expect
And register to come out and play!
Tom